330 ohm resistors are chosen in order to limit the current flowing through the LEDs to 10mA. The LEDs have a voltage drop of 1.8v.
Therefore there is 3.2v across the resistor (5 - 1.8 = 3.2).
V = IR, which can be rewritten as R = V/I.
Plugging in 10maA as 0.01 gives 3.2 / 0.01 which is 320 ohm. 330 is a close enough value.
| Component | Description | Image | 
|---|---|---|
| 0.01uF Cap (2x) | Bypass caps for level shifters | ![]()  | 
| LED (2x) | Battery / Status LEDs | ![]()  | 
| 330 ohm Resistor (2x) | Current limiting resistors for LEDs | ![]()  | 
| Reset Button | Momentary Switch | ![]()  | 
| 50 Pin Connector | Female Connector to Main Board | ![]()  |